Prove that (1+sec theta)/sec theta=

 

P. Prove that (1+sec theta)/sec theta=

                                                            (Our YouTube channel: Maths Solutions by HPL)



Note: The solution appears as the third problem in this video





Location: Andhra Pradesh, India

Comments

Post a Comment

Popular posts from this blog

A medicine capsule is in the shape of a cylinder

Image
    P.  A medicine capsule is in the shape of a cylinder with two hemi- spheres stuck to each of it's ends. The length of the capsule is 14mm and the width is 5mm. Find it's surface area (AP 2019 Public Exam Question) (For other Questions, you can find 10th Class ,      10th - CBSE Questions ,      10th Previous Years Questions ,           10th - Applications of Trigonometry ,       10th - Statistics ,      10th - Probability ,      10th - Mensuration ,      10th - Quadratic Equations ,      10th - Pair of Linear Equations in 2 Variables ,      10th - Similar Triangles ,      10th - Polynomials ,       10th - Progressions ,       10th - Sets ,       10th - Real Numbers ,       10th - Trigonometry ,    ...
Read more

Let ABCDEF be a regular hexagon with centre O, show that AB+AC+AD+AE+AF

Image
 P. Let ABCDEF be a regular hexagon with centre O, show that AB+AC+AD+AE+AF    (For other Questions, you can find    Jr. Inter Maths 1A  ,  Jr. Inter Maths 1B ,  Sr. Inter Maths2A  ,  Sr. Inter Maths2B    playlists in the You tube.)                                                                 (Our YouTube channel:   Maths Solutions by HPL ) Solutions to the below questions are also available in our You tube channel Maths 1A: 1.  If the points whose position vectors are 3i-2j-k,2i+3j-4k,-i+j+2k 2.   If a=2i+j-k, b=-i+2j-4k, c=i+j+k then find (a×b).(b×c) 3.  For A belongs to R, Prove that cosA.cos((π/3)+A).cos((π/3)-A)=1/4cos3A and 4.  Solve cot^2x-(√3+1)cotx+√3 5.  Prove that tan^(-1)(1/2) + tan^(-1)(1/5) + ta...
Read more

Show that the points (-4,-7), (-1,2), (8,5) and (5,-4) taken

Image
 P.  Show that the points (-4,-7), (-1,2), (8,5) and (5,-4) taken in order are the vertices of a rhombus. Find it's area. (Hint : Area of rhombus= (1/2) * product of it's diagonals) (AP 2015, 2018 Public Exam Question) (For other Questions, you can find 10th Class ,      10th - CBSE Questions ,      10th Previous Years Questions ,           10th - Applications of Trigonometry ,       10th - Statistics ,      10th - Probability ,      10th - Mensuration ,      10th - Quadratic Equations ,      10th - Pair of Linear Equations in 2 Variables ,      10th - Similar Triangles ,      10th - Polynomials ,       10th - Progressions ,       10th - Sets ,       10th - Real Numbers ,       10th - Trigonometry ,     ...
Read more